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-3n^2+11n+255=
We move all terms to the left:
-3n^2+11n+255-()=0
We add all the numbers together, and all the variables
-3n^2+11n=0
a = -3; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-3)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-3}=\frac{-22}{-6} =3+2/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-3}=\frac{0}{-6} =0 $
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